2/3(12y-15)

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Solution for 2/3(12y-15) equation: 


y in (-oo:+oo)

(2/3)*(12*y-15) = 0

2/3*(12*y-15) = 0

( 12*y-15 )

12*y-15 = 0 // + 15

12*y = 15 // : 12

y = 15/12

y = 5/4

( 2/3 )

2/3 = 0

y belongs to the empty set

y = 5/4

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