2/3(13+n)=-1/2n

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Solution for 2/3(13+n)=-1/2n equation:



2/3(13+n)=-1/2n
We move all terms to the left:
2/3(13+n)-(-1/2n)=0
Domain of the equation: 3(13+n)!=0
n∈R
Domain of the equation: 2n)!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
2/3(n+13)-(-1/2n)=0
We get rid of parentheses
2/3(n+13)+1/2n=0
We calculate fractions
4n/(6n^2+78n)+(3nn/(6n^2+78n)=0
We calculate terms in parentheses: +(3nn/(6n^2+78n), so:
3nn/(6n^2+78n
We multiply all the terms by the denominator
3nn
Back to the equation:
+(3nn)
We multiply all the terms by the denominator
4n+3nn*(6n^2+78n)=0
We multiply parentheses
18n^3+234n^2+4n=0
We do not support enpression: n^3

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