2/3(13+n)=-1/2n

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Solution for 2/3(13+n)=-1/2n equation: 



2/3(13+n)=-1/2n

We move all terms to the left:

2/3(13+n)-(-1/2n)=0



Domain of the equation: 3(13+n)!=0

n∈R





Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

2/3(n+13)-(-1/2n)=0

We get rid of parentheses

2/3(n+13)+1/2n=0

We calculate fractions


4n/(6n^2+78n)+(3nn/(6n^2+78n)=0



We calculate terms in parentheses: +(3nn/(6n^2+78n), so:

3nn/(6n^2+78n

We multiply all the terms by the denominator


3nn

Back to the equation:

+(3nn)



We multiply all the terms by the denominator


4n+3nn*(6n^2+78n)=0

We multiply parentheses

18n^3+234n^2+4n=0

We do not support enpression: n^3

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