2/3(15-6x)=-1/2(4x-10)

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Solution for 2/3(15-6x)=-1/2(4x-10) equation: 



2/3(15-6x)=-1/2(4x-10)

We move all terms to the left:

2/3(15-6x)-(-1/2(4x-10))=0



Domain of the equation: 3(15-6x)!=0

x∈R





Domain of the equation: 2(4x-10))!=0

x∈R



We add all the numbers together, and all the variables

2/3(-6x+15)-(-1/2(4x-10))=0

We calculate fractions


(4x4/(3(-6x+15)*2(4x-10)))+(-(-3x0)/(3(-6x+15)*2(4x-10)))=0



We calculate terms in parentheses: +(4x4/(3(-6x+15)*2(4x-10))), so:

4x4/(3(-6x+15)*2(4x-10))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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