2/3(15f-6)-2(f-4)=1/2(22+16f)

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Solution for 2/3(15f-6)-2(f-4)=1/2(22+16f) equation:



2/3(15f-6)-2(f-4)=1/2(22+16f)
We move all terms to the left:
2/3(15f-6)-2(f-4)-(1/2(22+16f))=0
Domain of the equation: 3(15f-6)!=0
f∈R
Domain of the equation: 2(22+16f))!=0
f∈R
We add all the numbers together, and all the variables
2/3(15f-6)-2(f-4)-(1/2(16f+22))=0
We multiply parentheses
2/3(15f-6)-2f-(1/2(16f+22))+8=0
We calculate fractions
-2f+(4f1/(3(15f-6)*2(16f+22)))+(-3f1/(3(15f-6)*2(16f+22)))+8=0
We calculate terms in parentheses: +(4f1/(3(15f-6)*2(16f+22))), so:
4f1/(3(15f-6)*2(16f+22))
We multiply all the terms by the denominator
4f1
We add all the numbers together, and all the variables
4f
Back to the equation:
+(4f)
We calculate terms in parentheses: +(-3f1/(3(15f-6)*2(16f+22))), so:
-3f1/(3(15f-6)*2(16f+22))
We multiply all the terms by the denominator
-3f1
We add all the numbers together, and all the variables
-3f
Back to the equation:
+(-3f)
We add all the numbers together, and all the variables
2f+(-3f)+8=0
We get rid of parentheses
2f-3f+8=0
We add all the numbers together, and all the variables
-1f+8=0
We move all terms containing f to the left, all other terms to the right
-f=-8
f=-8/-1
f=+8

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