2/3(15y-6)-3y=1/3(9-3y)

Solution for 2/3(15y-6)-3y=1/3(9-3y) equation:

2/3(15y-6)-3y=1/3(9-3y)

We move all terms to the left:

2/3(15y-6)-3y-(1/3(9-3y))=0


Domain of the equation: 3(15y-6)!=0

y∈R



Domain of the equation: 3(9-3y))!=0

y∈R


We add all the numbers together, and all the variables

2/3(15y-6)-3y-(1/3(-3y+9))=0

We add all the numbers together, and all the variables

-3y+2/3(15y-6)-(1/3(-3y+9))=0

We calculate fractions


-3y+(6y(-)/(3(15y-6)*3(-3y+9)))+(-3y1/(3(15y-6)*3(-3y+9)))=0


We calculate terms in parentheses: +(6y(-)/(3(15y-6)*3(-3y+9))), so:

6y(-)/(3(15y-6)*3(-3y+9))

We add all the numbers together, and all the variables

6y0/(3(15y-6)*3(-3y+9))

We multiply all the terms by the denominator


6y0

We add all the numbers together, and all the variables

6y

Back to the equation:

+(6y)



We calculate terms in parentheses: +(-3y1/(3(15y-6)*3(-3y+9))), so:

-3y1/(3(15y-6)*3(-3y+9))

We multiply all the terms by the denominator


-3y1

We add all the numbers together, and all the variables

-3y

Back to the equation:

+(-3y)


We add all the numbers together, and all the variables

3y+(-3y)=0

We get rid of parentheses

3y-3y=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0