2/3(15y-6)-3y=1/3(9-3y)

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Solution for 2/3(15y-6)-3y=1/3(9-3y) equation:



2/3(15y-6)-3y=1/3(9-3y)
We move all terms to the left:
2/3(15y-6)-3y-(1/3(9-3y))=0
Domain of the equation: 3(15y-6)!=0
y∈R
Domain of the equation: 3(9-3y))!=0
y∈R
We add all the numbers together, and all the variables
2/3(15y-6)-3y-(1/3(-3y+9))=0
We add all the numbers together, and all the variables
-3y+2/3(15y-6)-(1/3(-3y+9))=0
We calculate fractions
-3y+(6y(-)/(3(15y-6)*3(-3y+9)))+(-3y1/(3(15y-6)*3(-3y+9)))=0
We calculate terms in parentheses: +(6y(-)/(3(15y-6)*3(-3y+9))), so:
6y(-)/(3(15y-6)*3(-3y+9))
We add all the numbers together, and all the variables
6y0/(3(15y-6)*3(-3y+9))
We multiply all the terms by the denominator
6y0
We add all the numbers together, and all the variables
6y
Back to the equation:
+(6y)
We calculate terms in parentheses: +(-3y1/(3(15y-6)*3(-3y+9))), so:
-3y1/(3(15y-6)*3(-3y+9))
We multiply all the terms by the denominator
-3y1
We add all the numbers together, and all the variables
-3y
Back to the equation:
+(-3y)
We add all the numbers together, and all the variables
3y+(-3y)=0
We get rid of parentheses
3y-3y=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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