2/3(18x+12)=3/4(16x+4)

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Solution for 2/3(18x+12)=3/4(16x+4) equation: 



2/3(18x+12)=3/4(16x+4)

We move all terms to the left:

2/3(18x+12)-(3/4(16x+4))=0



Domain of the equation: 3(18x+12)!=0

x∈R





Domain of the equation: 4(16x+4))!=0

x∈R



We calculate fractions


(8x1/(3(18x+12)*4(16x+4)))+(-9x1/(3(18x+12)*4(16x+4)))=0



We calculate terms in parentheses: +(8x1/(3(18x+12)*4(16x+4))), so:

8x1/(3(18x+12)*4(16x+4))

We multiply all the terms by the denominator


8x1

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-9x1/(3(18x+12)*4(16x+4))), so:

-9x1/(3(18x+12)*4(16x+4))

We multiply all the terms by the denominator


-9x1

We add all the numbers together, and all the variables

-9x

Back to the equation:

+(-9x)



We get rid of parentheses

8x-9x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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