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2/3(18x-12)-2x=3(12+3x)-7
We move all terms to the left:
2/3(18x-12)-2x-(3(12+3x)-7)=0
Domain of the equation: 3(18x-12)!=0We add all the numbers together, and all the variables
x∈R
2/3(18x-12)-2x-(3(3x+12)-7)=0
We add all the numbers together, and all the variables
-2x+2/3(18x-12)-(3(3x+12)-7)=0
We multiply all the terms by the denominator
-2x*3(18x-12)-((3(3x+12)-7))*3(18x-12)+2=0
We calculate terms in parentheses: -((3(3x+12)-7))*3(18x-12), so:Wy multiply elements
(3(3x+12)-7))*3(18x-12
-6x^2(1-((3(3x+12)-7))*3(18x-12)+2=0
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