2/3(18x-6)=-1/2(-28x+10)

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Solution for 2/3(18x-6)=-1/2(-28x+10) equation: 



2/3(18x-6)=-1/2(-28x+10)

We move all terms to the left:

2/3(18x-6)-(-1/2(-28x+10))=0



Domain of the equation: 3(18x-6)!=0

x∈R





Domain of the equation: 2(-28x+10))!=0

x∈R



We calculate fractions


(4x(-)/(3(18x-6)*2(-28x+10)))+(-(-3x1)/(3(18x-6)*2(-28x+10)))=0



We calculate terms in parentheses: +(4x(-)/(3(18x-6)*2(-28x+10))), so:

4x(-)/(3(18x-6)*2(-28x+10))

We add all the numbers together, and all the variables

4x0/(3(18x-6)*2(-28x+10))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(-3x1)/(3(18x-6)*2(-28x+10))), so:

-(-3x1)/(3(18x-6)*2(-28x+10))

We add all the numbers together, and all the variables

-(-3x)/(3(18x-6)*2(-28x+10))

We multiply all the terms by the denominator


-(-3x)

We get rid of parentheses

3x

Back to the equation:

+(3x)



We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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