2/3(2-x)=-1/6(x+4)

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Solution for 2/3(2-x)=-1/6(x+4) equation: 



2/3(2-x)=-1/6(x+4)

We move all terms to the left:

2/3(2-x)-(-1/6(x+4))=0



Domain of the equation: 3(2-x)!=0

x∈R





Domain of the equation: 6(x+4))!=0

x∈R



We add all the numbers together, and all the variables

2/3(-1x+2)-(-1/6(x+4))=0

We calculate fractions


(12xx/(3(-1x+2)*6(x+4)))+(-(-3x0)/(3(-1x+2)*6(x+4)))=0



We calculate terms in parentheses: +(12xx/(3(-1x+2)*6(x+4))), so:

12xx/(3(-1x+2)*6(x+4))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-(-3x0)/(3(-1x+2)*6(x+4))), so:

-(-3x0)/(3(-1x+2)*6(x+4))

We add all the numbers together, and all the variables

-(-3x)/(3(-1x+2)*6(x+4))

We multiply all the terms by the denominator


-(-3x)

We get rid of parentheses

3x

Back to the equation:

+(3x)



We add all the numbers together, and all the variables

3x+12xx=0

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