2/3(25-x)=1x+2

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Solution for 2/3(25-x)=1x+2 equation: 



2/3(25-x)=1x+2

We move all terms to the left:

2/3(25-x)-(1x+2)=0



Domain of the equation: 3(25-x)!=0

x∈R



We add all the numbers together, and all the variables

2/3(-1x+25)-(x+2)=0

We get rid of parentheses

2/3(-1x+25)-x-2=0

We multiply all the terms by the denominator


-x*3(-1x+25)-2*3(-1x+25)+2=0

Wy multiply elements

-3x^2(--6x(-+2=0

We use the square of the difference formula

-3x^2(+6x(-2=0

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