2/3(2n-3)=1/2(3n+5)

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Solution for 2/3(2n-3)=1/2(3n+5) equation: 



2/3(2n-3)=1/2(3n+5)

We move all terms to the left:

2/3(2n-3)-(1/2(3n+5))=0



Domain of the equation: 3(2n-3)!=0

n∈R





Domain of the equation: 2(3n+5))!=0

n∈R



We calculate fractions


(4n3/(3(2n-3)*2(3n+5)))+(-3n2/(3(2n-3)*2(3n+5)))=0



We calculate terms in parentheses: +(4n3/(3(2n-3)*2(3n+5))), so:

4n3/(3(2n-3)*2(3n+5))

We multiply all the terms by the denominator


4n3

We add all the numbers together, and all the variables

4n^3

We do not support enpression: n^3

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