2/3(2x+1)+2(x-1)=36

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Solution for 2/3(2x+1)+2(x-1)=36 equation: 



2/3(2x+1)+2(x-1)=36

We move all terms to the left:

2/3(2x+1)+2(x-1)-(36)=0



Domain of the equation: 3(2x+1)!=0

x∈R



We multiply parentheses

2/3(2x+1)+2x-2-36=0

We multiply all the terms by the denominator


2x*3(2x+1)-2*3(2x+1)-36*3(2x+1)+2=0

Wy multiply elements

6x^2(2-6x(2-108x(2+2=0

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