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2/3(2x+1)=1/4(5x+5)
We move all terms to the left:
2/3(2x+1)-(1/4(5x+5))=0
Domain of the equation: 3(2x+1)!=0
x∈R
Domain of the equation: 4(5x+5))!=0We calculate fractions
x∈R
(8x5/(3(2x+1)*4(5x+5)))+(-3x2/(3(2x+1)*4(5x+5)))=0
We calculate terms in parentheses: +(8x5/(3(2x+1)*4(5x+5))), so:
8x5/(3(2x+1)*4(5x+5))
We multiply all the terms by the denominator
8x5
We add all the numbers together, and all the variables
8x^5
We do not support expression: x^5
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