2/3(2x+2)=3(3-4x)+19

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Solution for 2/3(2x+2)=3(3-4x)+19 equation: 


x in (-oo:+oo)

(2/3)*(2*x+2) = 3*(3-(4*x))+19 // - 3*(3-(4*x))+19

(2/3)*(2*x+2)-(3*(3-(4*x)))-19 = 0

(2/3)*(2*x+2)-3*(3-4*x)-19 = 0

2/3*(2*x+2)-3*(3-4*x)-19 = 0

2/3*(2*x+2)-3*(3-4*x)-19 = 0

40/3*x-19-23/3 = 0

40/3*x-80/3 = 0

40/3*x-80/3 = 0

40/3*x-80/3 = 0 // + 80/3

40/3*x = 80/3 // : 40/3

x = 80/3/40/3

x = 2

x = 2

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