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2/3(2x+9)=1/4(5x-6)
We move all terms to the left:
2/3(2x+9)-(1/4(5x-6))=0
Domain of the equation: 3(2x+9)!=0
x∈R
Domain of the equation: 4(5x-6))!=0We calculate fractions
x∈R
(8x5/(3(2x+9)*4(5x-6)))+(-3x2/(3(2x+9)*4(5x-6)))=0
We calculate terms in parentheses: +(8x5/(3(2x+9)*4(5x-6))), so:
8x5/(3(2x+9)*4(5x-6))
We multiply all the terms by the denominator
8x5
We add all the numbers together, and all the variables
8x^5
We do not support expression: x^5
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