2/3(2x-1)+7/3=7+1/2x

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Solution for 2/3(2x-1)+7/3=7+1/2x equation:


x in (-oo:+oo)

(2/3)*(2*x-1)+7/3 = (1/2)*x+7 // - (1/2)*x+7

(2/3)*(2*x-1)-((1/2)*x)+7/3-7 = 0

(2/3)*(2*x-1)+(-1/2)*x+7/3-7 = 0

2/3*(2*x-1)-x/2+7/3-7 = 0

(2/3*2*3*(2*x-1))/(2*3)+(3*(-x))/(2*3)+(2*7)/(2*3)+(-7*2*3)/(2*3) = 0

2/3*2*3*(2*x-1)+3*(-x)+2*7-7*2*3 = 0

5*x-42-4+14 = 0

5*x-42+10 = 0

5*x-32 = 0

(5*x-32)/(2*3) = 0

(5*x-32)/(2*3) = 0 // * 2*3

5*x-32 = 0

5*x-32 = 0 // + 32

5*x = 32 // : 5

x = 32/5

x = 32/5

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