2/3(2x-3)=4x+6

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Solution for 2/3(2x-3)=4x+6 equation: 



2/3(2x-3)=4x+6

We move all terms to the left:

2/3(2x-3)-(4x+6)=0



Domain of the equation: 3(2x-3)!=0

x∈R



We get rid of parentheses

2/3(2x-3)-4x-6=0

We multiply all the terms by the denominator


-4x*3(2x-3)-6*3(2x-3)+2=0

Wy multiply elements

-12x^2(2-18x(2+2=0

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