2/3(2x-5)=1/3(x+8)

Solution for 2/3(2x-5)=1/3(x+8) equation:

2/3(2x-5)=1/3(x+8)

We move all terms to the left:

2/3(2x-5)-(1/3(x+8))=0


Domain of the equation: 3(2x-5)!=0

x∈R



Domain of the equation: 3(x+8))!=0

x∈R


We calculate fractions


(6xx/(3(2x-5)*3(x+8)))+(-3x2/(3(2x-5)*3(x+8)))=0


We calculate terms in parentheses: +(6xx/(3(2x-5)*3(x+8))), so:

6xx/(3(2x-5)*3(x+8))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-3x2/(3(2x-5)*3(x+8))), so:

-3x2/(3(2x-5)*3(x+8))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)


We get rid of parentheses

-3x^2+6xx=0