2/3(3a-15)=4(2a+5)

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Solution for 2/3(3a-15)=4(2a+5) equation: 



2/3(3a-15)=4(2a+5)

We move all terms to the left:

2/3(3a-15)-(4(2a+5))=0



Domain of the equation: 3(3a-15)!=0

a∈R



We multiply all the terms by the denominator


-((4(2a+5)))*3(3a-15)+2=0



We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))*3(3a-15), so:

(4(2a+5)))*3(3a-15





We calculate terms in parentheses: -((4(2a+5)))

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