2/3(3k+3)=20

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Solution for 2/3(3k+3)=20 equation: 



2/3(3k+3)=20

We move all terms to the left:

2/3(3k+3)-(20)=0



Domain of the equation: 3(3k+3)!=0

k∈R



We multiply all the terms by the denominator


-20*3(3k+3)+2=0

Wy multiply elements

-60k(3+2=0

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