2/3(3k-1)3/2(2k-3)

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Solution for 2/3(3k-1)3/2(2k-3) equation: 


k in (-oo:+oo)

(2/3)*(3*k-1) > (3/2)*(2*k-3) // - (3/2)*(2*k-3)

(2/3)*(3*k-1)-((3/2)*(2*k-3)) > 0

(2/3)*(3*k-1)+(-3/2)*(2*k-3) > 0

2/3*(3*k-1)-3/2*(2*k-3) > 0

2/3*(3*k-1)-3/2*(2*k-3) > 0

23/6-k > 0

23/6-k > 0

23/6-k > 0

-k > -23/6 // * -1

k < 23/6

	(-oo:23/6)	(23/6:+oo)
23/6-k	+	-


k in (-oo:23/6)

(-oo:23/6)

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