2/3(3k-2)3/2(2k-3)

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Solution for 2/3(3k-2)3/2(2k-3) equation: 


k in (-oo:+oo)

(2/3)*(3*k-2) > (3/2)*(2*k-3) // - (3/2)*(2*k-3)

(2/3)*(3*k-2)-((3/2)*(2*k-3)) > 0

(2/3)*(3*k-2)+(-3/2)*(2*k-3) > 0

2/3*(3*k-2)-3/2*(2*k-3) > 0

2/3*(3*k-2)-3/2*(2*k-3) > 0

19/6-k > 0

19/6-k > 0

19/6-k > 0

-k > -19/6 // * -1

k < 19/6

	(-oo:19/6)	(19/6:+oo)
19/6-k	+	-


k in (-oo:19/6)

(-oo:19/6)

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