2/3(3m+3)=1/4(4m+28)

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Solution for 2/3(3m+3)=1/4(4m+28) equation: 



2/3(3m+3)=1/4(4m+28)

We move all terms to the left:

2/3(3m+3)-(1/4(4m+28))=0



Domain of the equation: 3(3m+3)!=0

m∈R





Domain of the equation: 4(4m+28))!=0

m∈R



We calculate fractions


(8m4/(3(3m+3)*4(4m+28)))+(-3m3/(3(3m+3)*4(4m+28)))=0



We calculate terms in parentheses: +(8m4/(3(3m+3)*4(4m+28))), so:

8m4/(3(3m+3)*4(4m+28))

We multiply all the terms by the denominator


8m4

We add all the numbers together, and all the variables

8m^4

We do not support empression: m^4

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