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2/3(3n-12)=3/4(4n-3)
We move all terms to the left:
2/3(3n-12)-(3/4(4n-3))=0
Domain of the equation: 3(3n-12)!=0
n∈R
Domain of the equation: 4(4n-3))!=0We calculate fractions
n∈R
(8n4/(3(3n-12)*4(4n-3)))+(-9n3/(3(3n-12)*4(4n-3)))=0
We calculate terms in parentheses: +(8n4/(3(3n-12)*4(4n-3))), so:
8n4/(3(3n-12)*4(4n-3))
We multiply all the terms by the denominator
8n4
We add all the numbers together, and all the variables
8n^4
We do not support enpression: n^4
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