2/3(3x+)9=-2(2x+6)

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Solution for 2/3(3x+)9=-2(2x+6) equation: 



2/3(3x+)9=-2(2x+6)

We move all terms to the left:

2/3(3x+)9-(-2(2x+6))=0



Domain of the equation: 3(3x+)9!=0

x∈R



We add all the numbers together, and all the variables

2/3(+3x)9-(-2(2x+6))=0

We multiply all the terms by the denominator


-((-2(2x+6)))*3(+3x)9+2=0

We move all terms containing x to the left, all other terms to the right

-((-2(2x+6)))*3(+3x)9=-2

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