2/3(3x+-5)=3

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Solution for 2/3(3x+-5)=3 equation: 



2/3(3x+-5)=3

We move all terms to the left:

2/3(3x+-5)-(3)=0



Domain of the equation: 3(3x+-5)!=0

x∈R



We add all the numbers together, and all the variables

2/3(3x-5)-3=0

We multiply all the terms by the denominator


-3*3(3x-5)+2=0

Wy multiply elements

-9x(3+2=0

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