2/3(3x+-6)=1/6(12x+6)

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Solution for 2/3(3x+-6)=1/6(12x+6) equation: 



2/3(3x+-6)=1/6(12x+6)

We move all terms to the left:

2/3(3x+-6)-(1/6(12x+6))=0



Domain of the equation: 3(3x+-6)!=0

x∈R





Domain of the equation: 6(12x+6))!=0

x∈R



We add all the numbers together, and all the variables

2/3(3x-6)-(1/6(12x+6))=0

We calculate fractions


(12x1/(3(3x-6)*6(12x+6)))+(-3x3/(3(3x-6)*6(12x+6)))=0



We calculate terms in parentheses: +(12x1/(3(3x-6)*6(12x+6))), so:

12x1/(3(3x-6)*6(12x+6))

We multiply all the terms by the denominator


12x1

We add all the numbers together, and all the variables

12x

Back to the equation:

+(12x)





We calculate terms in parentheses: +(-3x3/(3(3x-6)*6(12x+6))), so:

-3x3/(3(3x-6)*6(12x+6))

We multiply all the terms by the denominator


-3x3

We add all the numbers together, and all the variables

-3x^3

We do not support expression: x^3

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