2/3(3x+1)=3/4(2x+3)

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Solution for 2/3(3x+1)=3/4(2x+3) equation: 



2/3(3x+1)=3/4(2x+3)

We move all terms to the left:

2/3(3x+1)-(3/4(2x+3))=0



Domain of the equation: 3(3x+1)!=0

x∈R





Domain of the equation: 4(2x+3))!=0

x∈R



We calculate fractions


(8x2/(3(3x+1)*4(2x+3)))+(-9x3/(3(3x+1)*4(2x+3)))=0



We calculate terms in parentheses: +(8x2/(3(3x+1)*4(2x+3))), so:

8x2/(3(3x+1)*4(2x+3))

We multiply all the terms by the denominator


8x2

We add all the numbers together, and all the variables

8x^2

Back to the equation:

+(8x^2)





We calculate terms in parentheses: +(-9x3/(3(3x+1)*4(2x+3))), so:

-9x3/(3(3x+1)*4(2x+3))

We multiply all the terms by the denominator


-9x3

We add all the numbers together, and all the variables

-9x^3

We do not support expression: x^3

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