2/3(3x+12)=40

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Solution for 2/3(3x+12)=40 equation: 



2/3(3x+12)=40

We move all terms to the left:

2/3(3x+12)-(40)=0



Domain of the equation: 3(3x+12)!=0

x∈R



We multiply all the terms by the denominator


-40*3(3x+12)+2=0

Wy multiply elements

-120x(3+2=0

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