2/3(3x+6)=8+2x

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Solution for 2/3(3x+6)=8+2x equation: 


x in (-oo:+oo)

(2/3)*(3*x+6) = 2*x+8 // - 2*x+8

(2/3)*(3*x+6)-(2*x)-8 = 0

(2/3)*(3*x+6)-2*x-8 = 0

2/3*(3*x+6)-2*x-8 = 0

2/3*(3*x+6)-2*x-8 = 0

4-8 = 0

-4 = 0

-4 = 0

x belongs to the empty set

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