2/3(3x+9)=3/4(24-8x)

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Solution for 2/3(3x+9)=3/4(24-8x) equation: 



2/3(3x+9)=3/4(24-8x)

We move all terms to the left:

2/3(3x+9)-(3/4(24-8x))=0



Domain of the equation: 3(3x+9)!=0

x∈R





Domain of the equation: 4(24-8x))!=0

x∈R



We add all the numbers together, and all the variables

2/3(3x+9)-(3/4(-8x+24))=0

We calculate fractions


(8x(-)/(3(3x+9)*4(-8x+24)))+(-9x3/(3(3x+9)*4(-8x+24)))=0



We calculate terms in parentheses: +(8x(-)/(3(3x+9)*4(-8x+24))), so:

8x(-)/(3(3x+9)*4(-8x+24))

We add all the numbers together, and all the variables

8x0/(3(3x+9)*4(-8x+24))

We multiply all the terms by the denominator


8x0

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-9x3/(3(3x+9)*4(-8x+24))), so:

-9x3/(3(3x+9)*4(-8x+24))

We multiply all the terms by the denominator


-9x3

We add all the numbers together, and all the variables

-9x^3

We do not support expression: x^3

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