2/3(3x-2)+6=1/6(4x+24)

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Solution for 2/3(3x-2)+6=1/6(4x+24) equation: 



2/3(3x-2)+6=1/6(4x+24)

We move all terms to the left:

2/3(3x-2)+6-(1/6(4x+24))=0



Domain of the equation: 3(3x-2)!=0

x∈R





Domain of the equation: 6(4x+24))!=0

x∈R



We calculate fractions


(12x4/(3(3x-2)*6(4x+24)))+(-3x3/(3(3x-2)*6(4x+24)))+6=0



We calculate terms in parentheses: +(12x4/(3(3x-2)*6(4x+24))), so:

12x4/(3(3x-2)*6(4x+24))

We multiply all the terms by the denominator


12x4

We add all the numbers together, and all the variables

12x^4

We do not support expression: x^4

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