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2/3(3x-5)=1/3(8x-8)
We move all terms to the left:
2/3(3x-5)-(1/3(8x-8))=0
Domain of the equation: 3(3x-5)!=0
x∈R
Domain of the equation: 3(8x-8))!=0We calculate fractions
x∈R
(6x8/(3(3x-5)*3(8x-8)))+(-3x3/(3(3x-5)*3(8x-8)))=0
We calculate terms in parentheses: +(6x8/(3(3x-5)*3(8x-8))), so:
6x8/(3(3x-5)*3(8x-8))
We multiply all the terms by the denominator
6x8
We add all the numbers together, and all the variables
6x^8
We do not support expression: x^8
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