2/3(3x-6)=1/2(2x+10)

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Solution for 2/3(3x-6)=1/2(2x+10) equation:


x in (-oo:+oo)

(2/3)*(3*x-6) = (1/2)*(2*x+10) // - (1/2)*(2*x+10)

(2/3)*(3*x-6)-((1/2)*(2*x+10)) = 0

(2/3)*(3*x-6)+(-1/2)*(2*x+10) = 0

2/3*(3*x-6)-1/2*(2*x+10) = 0

2/3*(3*x-6)-1/2*(2*x+10) = 0

x-9 = 0

x-9 = 0

x-9 = 0 // + 9

x = 9

x = 9

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