2/3(3x-6)=1/7(21x-7)

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Solution for 2/3(3x-6)=1/7(21x-7) equation: 



2/3(3x-6)=1/7(21x-7)

We move all terms to the left:

2/3(3x-6)-(1/7(21x-7))=0



Domain of the equation: 3(3x-6)!=0

x∈R





Domain of the equation: 7(21x-7))!=0

x∈R



We calculate fractions


(14x2/(3(3x-6)*7(21x-7)))+(-3x3/(3(3x-6)*7(21x-7)))=0



We calculate terms in parentheses: +(14x2/(3(3x-6)*7(21x-7))), so:

14x2/(3(3x-6)*7(21x-7))

We multiply all the terms by the denominator


14x2

We add all the numbers together, and all the variables

14x^2

Back to the equation:

+(14x^2)





We calculate terms in parentheses: +(-3x3/(3(3x-6)*7(21x-7))), so:

-3x3/(3(3x-6)*7(21x-7))

We multiply all the terms by the denominator


-3x3

We add all the numbers together, and all the variables

-3x^3

We do not support expression: x^3

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