2/3(3x-7)=1/6(x+5)

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Solution for 2/3(3x-7)=1/6(x+5) equation: 



2/3(3x-7)=1/6(x+5)

We move all terms to the left:

2/3(3x-7)-(1/6(x+5))=0



Domain of the equation: 3(3x-7)!=0

x∈R





Domain of the equation: 6(x+5))!=0

x∈R



We calculate fractions


(12xx/(3(3x-7)*6(x+5)))+(-3x3/(3(3x-7)*6(x+5)))=0



We calculate terms in parentheses: +(12xx/(3(3x-7)*6(x+5))), so:

12xx/(3(3x-7)*6(x+5))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-3x3/(3(3x-7)*6(x+5))), so:

-3x3/(3(3x-7)*6(x+5))

We multiply all the terms by the denominator


-3x3

We add all the numbers together, and all the variables

-3x^3

We do not support expression: x^3

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