2/3(3x-9)=4x+18

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Solution for 2/3(3x-9)=4x+18 equation: 



2/3(3x-9)=4x+18

We move all terms to the left:

2/3(3x-9)-(4x+18)=0



Domain of the equation: 3(3x-9)!=0

x∈R



We get rid of parentheses

2/3(3x-9)-4x-18=0

We multiply all the terms by the denominator


-4x*3(3x-9)-18*3(3x-9)+2=0

Wy multiply elements

-12x^2(3-54x(3+2=0

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