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2/3(3y-12)=y-5
We move all terms to the left:
2/3(3y-12)-(y-5)=0
Domain of the equation: 3(3y-12)!=0We get rid of parentheses
y∈R
2/3(3y-12)-y+5=0
We multiply all the terms by the denominator
-y*3(3y-12)+5*3(3y-12)+2=0
Wy multiply elements
-3y^2(3+15y(3+2=0
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