2/3(4d-1)-3/4(2d+5)=14d-53/12

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Solution for 2/3(4d-1)-3/4(2d+5)=14d-53/12 equation: 



2/3(4d-1)-3/4(2d+5)=14d-53/12

We move all terms to the left:

2/3(4d-1)-3/4(2d+5)-(14d-53/12)=0



Domain of the equation: 3(4d-1)!=0

d∈R





Domain of the equation: 4(2d+5)!=0

d∈R



We add all the numbers together, and all the variables

2/3(4d-1)-3/4(2d+5)-(+14d-53/12)=0

We get rid of parentheses

2/3(4d-1)-3/4(2d+5)-14d+53/12=0

We calculate fractions


-14d+(96d2/(3(4d-1)*4(2d+5)*12)+(-108d4/(3(4d-1)*4(2d+5)*12)+(636d^24/(3(4d-1)*4(2d+5)*12)=0



We calculate terms in parentheses: +(96d2/(3(4d-1)*4(2d+5)*12)+(-108d4/(3(4d-1)*4(2d+5)*12)+(636d^24/(3(4d-1)*4(2d+5)*12), so:

96d2/(3(4d-1)*4(2d+5)*12)+(-108d4/(3(4d-1)*4(2d+5)*12)+(636d^24/(3(4d-1)*4(2d+5)*12

We do not support edpression: d^24

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