2/3(4x+2)-2x=5(2x-4)+6

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Solution for 2/3(4x+2)-2x=5(2x-4)+6 equation: 



2/3(4x+2)-2x=5(2x-4)+6

We move all terms to the left:

2/3(4x+2)-2x-(5(2x-4)+6)=0



Domain of the equation: 3(4x+2)!=0

x∈R



We add all the numbers together, and all the variables

-2x+2/3(4x+2)-(5(2x-4)+6)=0

We multiply all the terms by the denominator


-2x*3(4x+2)-((5(2x-4)+6))*3(4x+2)+2=0



We calculate terms in parentheses: -((5(2x-4)+6))*3(4x+2), so:

(5(2x-4)+6))*3(4x+2



Wy multiply elements

-6x^2(4-((5(2x-4)+6))*3(4x+2)+2=0

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