2/3(4x-1)-(4x-(1-3x)/2)=x-7

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Solution for 2/3(4x-1)-(4x-(1-3x)/2)=x-7 equation:


x in (-oo:+oo)

(2/3)*(4*x-1)+(1-(3*x))/2-(4*x) = x-7 // - x-7

(2/3)*(4*x-1)+(1-(3*x))/2-(4*x)-x+7 = 0

(2/3)*(4*x-1)+(1-3*x)/2-4*x-x+7 = 0

2/3*(4*x-1)+(1-3*x)/2-4*x-x+7 = 0

(2/3*2*(4*x-1))/2+(1-3*x)/2+(-4*2*x)/2+(2*(-x))/2+(2*7)/2 = 0

2/3*2*(4*x-1)-3*x-4*2*x+2*(-x)+2*7+1 = 0

7/3*x-8*x-2*x-1/3+14 = 0

14-17/3*x-2*x-1/3 = 0

14-23/3*x-1/3 = 0

41/3-23/3*x = 0

(41/3-23/3*x)/2 = 0

(41/3-23/3*x)/2 = 0 // * 2

41/3-23/3*x = 0

41/3-23/3*x = 0 // - 41/3

-23/3*x = -41/3 // : -23/3

x = -41/3/(-23/3)

x = 41/23

x = 41/23

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