2/3(4x-1)-(4x-(1-3x/2))=(x-7/2)

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Solution for 2/3(4x-1)-(4x-(1-3x/2))=(x-7/2) equation: 



2/3(4x-1)-(4x-(1-3x/2))=(x-7/2)

We move all terms to the left:

2/3(4x-1)-(4x-(1-3x/2))-((x-7/2))=0



Domain of the equation: 3(4x-1)!=0

x∈R



We add all the numbers together, and all the variables

2/3(4x-1)-(4x-(-3x/2+1))-((+x-7/2))=0

We calculate fractions

We do not support expression: x^24

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