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2/3(4x-1)3x=5/4-(x+2)
We move all terms to the left:
2/3(4x-1)3x-(5/4-(x+2))=0
Domain of the equation: 3(4x-1)3x!=0
x∈R
Domain of the equation: 4-(x+2))!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
-(x+2))!=-4
x∈R
(-(x+2))-1x+3(4x-1)3x*4)+(-(5*3(4x-1)3x)/(-1x+3(4x-1)3x*4)+2*4)/(=0
We calculate terms in parentheses: +(-(x+2)), so:
-(x+2)
We get rid of parentheses
-x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
+(-1x-2)
We calculate terms in parentheses: -(5*3(4x-1)3x)/(-1x+3(4x-1)3x*4), so:We add all the numbers together, and all the variables
5*3(4x-1)3x)/(-1x+3(4x-1)3x*4
We add all the numbers together, and all the variables
-1x+5*3(4x-1)3x)/(+3(4x-1)3x*4
We multiply all the terms by the denominator
-1x*(+5*3(4x-1)3x)+(3(4x-1)3x*4)*(
Back to the equation:
-(-1x*(+5*3(4x-1)3x)+(3(4x-1)3x*4)*()
-1x+(-1x-2)+3(4x-1)3x*4)+(-(-1x*(+5*3(4x-1)3x)+(3(4x-1)3x*4)*()+2*4)/(=0
We get rid of parentheses
-1x-1x+3(4x-1)3x*4)+(-(-1x*(+5*3(4x-1)3x)+(3(4x-1)3x*4)*()+2*4)/(-2=0
We multiply all the terms by the denominator
-1x*(-2-1x*(-2+(3(4x-1)3x*4)+()*(-2-(-1x*(+5*3(4x-1)3x)+(3(4x-1)3x*4)*()+2*4)=0
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