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2/3(4x-1)=2/9(5x+4)
We move all terms to the left:
2/3(4x-1)-(2/9(5x+4))=0
Domain of the equation: 3(4x-1)!=0
x∈R
Domain of the equation: 9(5x+4))!=0We calculate fractions
x∈R
(18x5/(3(4x-1)*9(5x+4)))+(-6x4/(3(4x-1)*9(5x+4)))=0
We calculate terms in parentheses: +(18x5/(3(4x-1)*9(5x+4))), so:
18x5/(3(4x-1)*9(5x+4))
We multiply all the terms by the denominator
18x5
We add all the numbers together, and all the variables
18x^5
We do not support expression: x^5
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