2/3(4x-2)=-3/4(-3x+8)

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Solution for 2/3(4x-2)=-3/4(-3x+8) equation:



2/3(4x-2)=-3/4(-3x+8)
We move all terms to the left:
2/3(4x-2)-(-3/4(-3x+8))=0
Domain of the equation: 3(4x-2)!=0
x∈R
Domain of the equation: 4(-3x+8))!=0
x∈R
We calculate fractions
(8x(-)/(3(4x-2)*4(-3x+8)))+(-(-9x4)/(3(4x-2)*4(-3x+8)))=0
We calculate terms in parentheses: +(8x(-)/(3(4x-2)*4(-3x+8))), so:
8x(-)/(3(4x-2)*4(-3x+8))
We add all the numbers together, and all the variables
8x0/(3(4x-2)*4(-3x+8))
We multiply all the terms by the denominator
8x0
We add all the numbers together, and all the variables
8x
Back to the equation:
+(8x)
We calculate terms in parentheses: +(-(-9x4)/(3(4x-2)*4(-3x+8))), so:
-(-9x4)/(3(4x-2)*4(-3x+8))
We add all the numbers together, and all the variables
-(-9x^4)/(3(4x-2)*4(-3x+8))
We multiply all the terms by the denominator
-(-9x^4)
We do not support expression: x^4

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