2/3(4x-2)=-3/4(-3x+8)

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Solution for 2/3(4x-2)=-3/4(-3x+8) equation: 



2/3(4x-2)=-3/4(-3x+8)

We move all terms to the left:

2/3(4x-2)-(-3/4(-3x+8))=0



Domain of the equation: 3(4x-2)!=0

x∈R





Domain of the equation: 4(-3x+8))!=0

x∈R



We calculate fractions


(8x(-)/(3(4x-2)*4(-3x+8)))+(-(-9x4)/(3(4x-2)*4(-3x+8)))=0



We calculate terms in parentheses: +(8x(-)/(3(4x-2)*4(-3x+8))), so:

8x(-)/(3(4x-2)*4(-3x+8))

We add all the numbers together, and all the variables

8x0/(3(4x-2)*4(-3x+8))

We multiply all the terms by the denominator


8x0

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-(-9x4)/(3(4x-2)*4(-3x+8))), so:

-(-9x4)/(3(4x-2)*4(-3x+8))

We add all the numbers together, and all the variables

-(-9x^4)/(3(4x-2)*4(-3x+8))

We multiply all the terms by the denominator


-(-9x^4)

We do not support expression: x^4

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