2/3(5-k)=7

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Solution for 2/3(5-k)=7 equation: 



2/3(5-k)=7

We move all terms to the left:

2/3(5-k)-(7)=0



Domain of the equation: 3(5-k)!=0

k∈R



We add all the numbers together, and all the variables

2/3(-1k+5)-7=0

We multiply all the terms by the denominator


-7*3(-1k+5)+2=0

Wy multiply elements

-21k(-+2=0

We use the square of the difference formula

-21k(-2=0

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