2/3(5c-12)=-10-1/6c

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Solution for 2/3(5c-12)=-10-1/6c equation: 



2/3(5c-12)=-10-1/6c

We move all terms to the left:

2/3(5c-12)-(-10-1/6c)=0



Domain of the equation: 3(5c-12)!=0

c∈R





Domain of the equation: 6c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

2/3(5c-12)-(-1/6c-10)=0

We get rid of parentheses

2/3(5c-12)+1/6c+10=0

We calculate fractions


12c/(90c^2-216c)+(3c5/(90c^2-216c)+10=0

We calculate fractions

We do not support ecpression: c^3

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