2/3(5n-1)=-3/6(n+2)

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Solution for 2/3(5n-1)=-3/6(n+2) equation: 



2/3(5n-1)=-3/6(n+2)

We move all terms to the left:

2/3(5n-1)-(-3/6(n+2))=0



Domain of the equation: 3(5n-1)!=0

n∈R





Domain of the equation: 6(n+2))!=0

n∈R



We calculate fractions


(12nn/(3(5n-1)*6(n+2)))+(-(-9n5)/(3(5n-1)*6(n+2)))=0



We calculate terms in parentheses: +(12nn/(3(5n-1)*6(n+2))), so:

12nn/(3(5n-1)*6(n+2))

We multiply all the terms by the denominator


12nn

Back to the equation:

+(12nn)





We calculate terms in parentheses: +(-(-9n5)/(3(5n-1)*6(n+2))), so:

-(-9n5)/(3(5n-1)*6(n+2))

We add all the numbers together, and all the variables

-(-9n^5)/(3(5n-1)*6(n+2))

We multiply all the terms by the denominator


-(-9n^5)

We do not support enpression: n^5

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