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2/3(5x+11)-2x=6(x+2)
We move all terms to the left:
2/3(5x+11)-2x-(6(x+2))=0
Domain of the equation: 3(5x+11)!=0We add all the numbers together, and all the variables
x∈R
-2x+2/3(5x+11)-(6(x+2))=0
We multiply all the terms by the denominator
-2x*3(5x+11)-((6(x+2)))*3(5x+11)+2=0
We calculate terms in parentheses: -((6(x+2)))*3(5x+11), so:Wy multiply elements
(6(x+2)))*3(5x+11
-6x^2(5-((6(x+2)))*3(5x+11)+2=0
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