2/3(5x+2)=1/3(7x+1)

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Solution for 2/3(5x+2)=1/3(7x+1) equation: 


x in (-oo:+oo)

(2/3)*(5*x+2) = (1/3)*(7*x+1) // - (1/3)*(7*x+1)

(2/3)*(5*x+2)-((1/3)*(7*x+1)) = 0

(2/3)*(5*x+2)+(-1/3)*(7*x+1) = 0

2/3*(5*x+2)-1/3*(7*x+1) = 0

2/3*(5*x+2)-1/3*(7*x+1) = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x = -1

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